Luke TB Posted April 20, 2013 Posted April 20, 2013 Sorry there is probably already a thread about this. I'm using an IC consumer hooked up to an energy bridge to a BC producer to power the quarry but how much solar power will I need using this set up to power the quarry efficiently? One Medium voltage array? Two? Quote
Lethosos Posted April 20, 2013 Posted April 20, 2013 AFAIK quarrys can take in at least 1MJ, but the more you pump into it at once, the faster it goes. Quote
theprolo Posted April 20, 2013 Posted April 20, 2013 Quarries use up to 32 MJ/t now I think, so as long as you get 1MJ/t in there, any more will just speed it up. Quote
Random Encounter Posted April 20, 2013 Posted April 20, 2013 This lists the energy requirements for a BC Quarry. 2 MJ = 5 EU as per the energy bridge. A single MV array would produce 64 EU/t, would be about 25 MJ/t. Slap on two redstone energy conduits (one set to input the other to output) and it would run at a decent rate. Two MV arrays would cap out the quarry's input, movement, and dig speed. vvvvvvv You're right, having the producer right up against the quarry, then there is no reason for any sort of conduit. Quote
Luke TB Posted April 20, 2013 Author Posted April 20, 2013 By cap out do you mean maximize or make it blow up? and why do I need energy conduits if I'm using the energy bridge onsumer and producer? Quote
Discord Moderator plowmanplow Posted April 20, 2013 Discord Moderator Posted April 20, 2013 The conversion rate from EU to MJ is 2.5:1 in non-lossy systems. Quarries will never blow up, but will not get any speed boost past a smidge over 48 MJ/t which yields about 5 blocks/second harvest rate. Quote
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